Mathematics.

series

Power Series

Calculus II35 minDifficulty6 out of 10

You should know: series convergence tests

Overview

A power series is an infinite series whose terms are powers of (x − a) multiplied by coefficients: Σcₙ(x−a)ⁿ. Unlike a numerical series, a power series defines a function of x, and it converges for x within a specific radius of a and diverges outside it. Power series are the algebraic backbone of Taylor series and let you manipulate transcendental functions (differentiate, integrate, solve differential equations) using term-by-term polynomial-like rules.

Intuition

Think of a power series as an 'infinite-degree polynomial' whose coefficients cₙ encode a function. Close to the center a, the powers (x−a)ⁿ shrink rapidly (if |x−a| is small) and the series behaves well; far from a, the powers grow and can overwhelm the coefficients, causing divergence. The radius of convergence R marks exactly where this tug-of-war between shrinking powers and coefficient size tips over — the series converges for |x−a| < R and diverges for |x−a| > R.

Interactive Graph

Maclaurin partial sums converging to sin(x)

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Formal Definition

Definition

A power series centered at a:

n=0cn(xa)n=c0+c1(xa)+c2(xa)2+\sum_{n=0}^{\infty} c_n (x-a)^n = c_0 + c_1(x-a) + c_2(x-a)^2 + \cdots

cₙ are constant coefficients; the series is a function of x

R=1limncn+1/cnR = \frac{1}{\lim_{n\to\infty} |c_{n+1}/c_n|}

Radius of convergence via the ratio test (when this limit exists)

Notation

NotationMeaning
cnc_nThe n-th coefficient of the power series
RRRadius of convergence — the series converges for |x−a| < R
(aR, a+R)(a-R,\ a+R)The set of x for which the series converges; endpoints must be checked individually

Derivation

Applying the ratio test directly to a power series Σcₙ(x−a)ⁿ to find its radius of convergence:

limncn+1(xa)n+1cn(xa)n=xalimncn+1cn\lim_{n\to\infty}\left|\frac{c_{n+1}(x-a)^{n+1}}{c_n(x-a)^n}\right| = |x-a|\lim_{n\to\infty}\left|\frac{c_{n+1}}{c_n}\right|

Factor out |x-a| from the ratio test limit

Converges when xalimcn+1cn<1    xa<1limcn+1/cn=R\text{Converges when } |x-a| \cdot \lim\left|\frac{c_{n+1}}{c_n}\right| < 1 \iff |x-a| < \frac{1}{\lim|c_{n+1}/c_n|} = R

Solving the ratio-test inequality for x gives exactly the radius of convergence

Properties

Term-by-term differentiation

ddxn=0cn(xa)n=n=1ncn(xa)n1\frac{d}{dx}\sum_{n=0}^{\infty} c_n(x-a)^n = \sum_{n=1}^{\infty} n c_n (x-a)^{n-1}

Condition: valid within the same radius of convergence R

Term-by-term integration

n=0cn(xa)ndx=C+n=0cnn+1(xa)n+1\int \sum_{n=0}^{\infty} c_n(x-a)^n\,dx = C + \sum_{n=0}^{\infty} \frac{c_n}{n+1}(x-a)^{n+1}

Condition: valid within the same radius of convergence R

Uniqueness

If cn(xa)n=dn(xa)n on an interval around a, then cn=dn for all n\text{If } \sum c_n(x-a)^n = \sum d_n(x-a)^n \text{ on an interval around } a, \text{ then } c_n = d_n \text{ for all } n

Applications

Solving linear differential equations (e.g. the quantum harmonic oscillator, Legendre's equation) via the power series (Frobenius) method, assuming a solution y = Σcₙxⁿ and matching coefficients.

Worked Examples

  1. Apply the ratio test to |aₙ₊₁/aₙ|.

    (x2)n+1/(n+1)2(x2)n/n2=x2n2(n+1)2x2\left|\frac{(x-2)^{n+1}/(n+1)^2}{(x-2)^n/n^2}\right| = |x-2|\cdot\frac{n^2}{(n+1)^2} \to |x-2|
  2. Converges when |x-2| < 1, so R = 1, centered at a=2.

    R=1,1<x<3 (before endpoint check)R = 1, \quad 1 < x < 3 \text{ (before endpoint check)}
  3. Check endpoints: at x=1 and x=3, series becomes Σ(±1)ⁿ/n², which converges absolutely (p-series, p=2>1) at both.

    Interval of convergence: [1,3]\text{Interval of convergence: } [1,3]

Answer: R = 1, interval of convergence [1, 3]

Practice Problems

Difficulty 5/10

Find the radius of convergence of Σ xⁿ/n!.

Difficulty 6/10

Find the interval of convergence of Σ (-1)ⁿ (x+1)ⁿ / n.

Common Mistakes

Common Mistake

Forgetting to check the endpoints of the interval of convergence separately.

The ratio/root test only determines the open interval (a-R, a+R). Each endpoint x=a±R must be substituted in and tested individually with a different convergence test (usually p-series or alternating series test), since the ratio test itself is inconclusive there (L=1).

Common Mistake

Assuming term-by-term differentiation or integration changes the radius of convergence.

Differentiating or integrating a power series term-by-term preserves the SAME radius of convergence R, though convergence AT the endpoints can change.

Quiz

The radius of convergence R of a power series Σcₙ(x−a)ⁿ tells you:
Why are power series so useful in computation (calculators, simulations)?

Historical Background

Power series appeared implicitly in Newton's and Gregory's work on infinite series expansions in the 1660s-70s, well before the underlying convergence theory existed. The rigorous notion of a radius of convergence was developed by Cauchy in the 1820s and sharpened by Abel, whose 1826 theorem on the behavior of power series at the boundary of convergence remains a cornerstone result.

  1. 1670s

    Newton and Gregory manipulate infinite series expansions of functions

    Isaac Newton, James Gregory

  2. 1821

    Cauchy formalizes convergence and introduces the radius of convergence concept

    Augustin-Louis Cauchy

  3. 1826

    Abel proves his theorem on continuity of power series at the boundary of convergence

    Niels Henrik Abel

Summary

  • A power series Σcₙ(x−a)ⁿ defines a function of x, converging within a radius R of the center a.
  • The ratio test on the coefficients typically determines R; endpoints x = a ± R must be checked separately.
  • Within the radius of convergence, power series can be differentiated and integrated term by term, preserving R.
  • Power series coefficients are unique — two power series equal on an interval must have identical coefficients.
  • Power series underlie Taylor series and the power-series (Frobenius) method for solving differential equations.

References