parametric and polar
Parametric Equations
You should know: functions, coordinate plane
Overview
A parametric curve describes x and y (and possibly z) each as separate functions of a third variable, the parameter t — typically thought of as time. Instead of y = f(x), you write x = x(t), y = y(t). This lets you describe curves that fail the vertical line test (circles, loops, cusps) and naturally encodes motion: position, velocity, and speed all fall out of differentiating the parametric functions.
Intuition
Imagine tracking a bug crawling on a table: at each moment t, it has an x-coordinate and a y-coordinate. Plotting (x(t), y(t)) for all t traces the bug's path. This is fundamentally different from y=f(x), which requires exactly one y for each x — a parametric curve can loop back, cross itself, or retrace, because the parameter t supplies the 'when', decoupling the path's shape from any functional restriction on x and y.
Interactive Graph
Formal Definition
A parametric curve in the plane is a pair of functions of a parameter t:
Each point on the curve corresponds to one value of t
Chain rule applied to eliminate t, valid where x'(t) ≠ 0
Second derivative requires differentiating dy/dx with respect to t again, then dividing by dx/dt
Total distance traveled along the curve from t=α to t=β
Notation
| Notation | Meaning |
|---|---|
| Coordinate functions of the parameter t | |
| Slope of the tangent line, computed without eliminating t |
Derivation
The arc length formula follows from approximating the curve by straight segments and taking a limit, exactly as with Riemann sums:
Distance formula on each small segment, rewritten in terms of Δt
The Riemann sum converges to the arc length integral as Δt → 0
Properties
Non-uniqueness of parametrization
Condition: e.g. (cos t, sin t) and (cos 2t, sin 2t) both trace the unit circle, at different speeds
Horizontal/vertical tangents
Applications
Worked Examples
Differentiate each component with respect to t.
Apply the parametric slope formula.
Substitute t = 1.
Answer: dy/dx = 0 at t=1 (a horizontal tangent)
Practice Problems
Find dy/dx for x = e^t, y = t·e^t at t = 0.
A particle moves with x(t) = t² − 4t, y(t) = 2t. Find the arc length traveled from t=0 to t=2.
Common Mistakes
Computing d²y/dx² by simply differentiating dy/dx with respect to t (forgetting to divide by dx/dt again).
d²y/dx² = [d/dt(dy/dx)] / (dx/dt), NOT d/dt(dy/dx) alone — the chain rule must be applied a second time.
Assuming arc length only requires ∫√(1+(dy/dx)²)dx as in the Cartesian case.
For parametric curves, use L=∫√(x'(t)²+y'(t)²)dt directly — converting to the Cartesian arc-length formula is often impossible or unnecessarily complicated when x(t) isn't invertible.
Historical Background
Parametric descriptions of curves arose naturally from mechanics — describing the path of a projectile or a point on a rolling wheel (the cycloid) required expressing x and y in terms of time rather than each other. Roberval, Pascal, and Huygens studied the cycloid parametrically in the 17th century, and Euler formalized the general parametric approach to curves in the 18th century as part of his systematic treatment of analytic geometry.
- 1630s-1650s
Roberval, Torricelli, and Pascal study the cycloid using motion-based (parametric) descriptions
Gilles de Roberval, Blaise Pascal
- 1748
Euler systematizes parametric curves in Introductio in analysin infinitorum
Leonhard Euler
Summary
- Parametric equations describe x and y as separate functions of a parameter t, allowing curves that aren't graphs of functions.
- Slope: dy/dx = y'(t)/x'(t) (chain rule), valid where x'(t) ≠ 0.
- Second derivative requires re-dividing by dx/dt after differentiating dy/dx with respect to t.
- Arc length: L = ∫√(x'(t)² + y'(t)²) dt over the parameter interval.
- The same curve can have many different parametrizations tracing it at different speeds or directions.
Mathematics