Mathematics.

integral calculus

Arc Length

Calculus II20 minDifficulty5 out of 10

You should know: integral, derivative

Overview

The arc length formula computes the exact length of a curve y=f(x) over an interval [a,b] by integrating the local stretching factor √(1+[f'(x)]²), which accounts for how much longer a small piece of curve is than its horizontal projection.

Interactive Graph

x^1.5 — the curve whose length we're measuring

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Formal Definition

Definition

For a smooth curve y=f(x) on [a,b], the arc length is:

L=ab1+[f(x)]2dxL = \int_a^b \sqrt{1 + [f'(x)]^2}\,dx
Arc Length Formula

Worked Examples

  1. Compute f'(x) = (3/2)x^(1/2), so [f'(x)]² = (9/4)x.

    f(x)=32x1/2,[f(x)]2=94xf'(x)=\frac32 x^{1/2},\quad [f'(x)]^2 = \frac94 x
  2. Set up the arc length integral.

    L=041+94xdxL = \int_0^4 \sqrt{1+\frac94 x}\,dx
  3. Substitute u=1+(9/4)x, du=(9/4)dx.

    L=49110udu=4923u3/2110L = \frac{4}{9}\int_1^{10} \sqrt{u}\,du = \frac49\cdot\frac23 u^{3/2}\Big|_1^{10}
  4. Evaluate.

    =827(103/21)= \frac{8}{27}(10^{3/2}-1)

Answer: L = (8/27)(10√10 - 1) ≈ 9.07

Practice Problems

Difficulty 5/10

Set up (but do not evaluate) the arc length integral for y = x² from x=0 to x=2.

Difficulty 5/10

A highway horizontal curve is a circular arc of radius R = 300 m subtending a central angle of 40°. Find the length of the curve (the distance a car actually travels around it).

Difficulty 7/10

A cable hangs as a shallow parabola y = 0.01x² between towers at x = −50 m and x = 50 m. Set up the integral for its length, and explain why the cable is longer than the 100 m tower spacing.

Quiz

The length of a circular highway curve of radius R and central angle θ (in radians) is:
Why is the arc length of any sloped curve always greater than its horizontal span?

Summary

  • Arc length L = ∫ₐᵇ √(1+[f'(x)]²) dx accounts for the extra length a curve has compared to its horizontal projection.
  • The formula comes from approximating the curve with tiny straight-line segments (via the Pythagorean theorem) and taking the limit as the segments shrink — essentially a Riemann sum.
  • Many arc length integrals don't have elementary closed forms and require numerical methods or substitution techniques.

References