integral calculus
Fundamental Theorem of Calculus
You should know: derivative, integral
Overview
The Fundamental Theorem of Calculus (FTC) is the bridge connecting differentiation and integration, proving they are inverse operations. It has two parts: Part 1 says the derivative of an integral (with variable upper limit) gives back the original function; Part 2 gives a practical method for evaluating definite integrals using antiderivatives — the technique used in essentially every introductory calculus computation.
Intuition
Imagine filling a bathtub. The RATE water flows in (gallons per minute) is like a derivative — it tells you how fast the water level is changing at any instant. The TOTAL amount of water in the tub at time T is like an integral of that flow rate from 0 to T. The Fundamental Theorem says: if you know the total-water-so-far function, its rate of change (derivative) IS the flow rate function you started with. Filling and totaling are inverse processes — exactly like squaring and square-rooting.
Interactive Graph
Formal Definition
Part 1 (differentiating an integral) and Part 2 (evaluating an integral):
If f is continuous, the derivative of its accumulation function gives back f itself
where F is any antiderivative of f (i.e. F' = f)
Notation
| Notation | Meaning |
|---|---|
| Evaluation bar notation — antiderivative evaluated at the bounds |
Proofs
- (Define the accumulation function)
- (G is itself an antiderivative of f)
- (Two antiderivatives of the same function differ only by a constant)
- (The constants cancel, and G(a)=0 since the integral from a to a is zero)
Properties
Existence of antiderivatives for continuous functions
Applications
Worked Examples
Find an antiderivative of 3x²: F(x) = x³.
Evaluate F(2) - F(0).
Answer: 8
Practice Problems
Evaluate ∫₀^π sin(x) dx.
Water flows into a tank at rate r(t) = 2t litres/min. Using the Fundamental Theorem of Calculus, how many litres enter between t = 0 and t = 5 min?
A beam's bending moment M(x) has dM/dx = V(x), the shear force. If V(x) = 400 − 50x (N) along a beam, find the change in moment from x = 0 to x = 4 m.
Common Mistakes
Confusing which part of FTC applies — trying to use Part 2's bounds-evaluation on a Part 1-style variable-limit derivative problem.
Part 1 is about differentiating an integral (no bounds evaluation needed — the answer is just the integrand). Part 2 is about evaluating an integral numerically using an antiderivative.
Quiz
Flashcards
Historical Background
James Gregory proved a geometric version of the theorem in 1668. Isaac Barrow, Newton's teacher at Cambridge, proved a more general geometric version around 1670. But it was Newton and Leibniz who recognized the theorem's full power — that it turns integration from a laborious geometric limiting process into simple algebraic antidifferentiation — and built the rest of calculus around that insight.
- 1668
James Gregory publishes a geometric proof of a special case
James Gregory
- c. 1670
Isaac Barrow proves a more general geometric version
Isaac Barrow
- 1670s-1680s
Newton and Leibniz recognize and exploit the full computational power of the theorem
Isaac Newton, Gottfried Wilhelm Leibniz
Summary
- The Fundamental Theorem of Calculus proves differentiation and integration are inverse operations.
- Part 1: the derivative of an accumulation function ∫ₐˣf(t)dt returns f(x) itself.
- Part 2: ∫ₐᵇf(x)dx = F(b) - F(a) for any antiderivative F — this is how definite integrals are actually computed in practice.
- Guarantees every continuous function has an antiderivative.
- Turned integration from a laborious limiting process into simple algebra.
Mathematics