discrete time processes
Optional Stopping Theorem
You should know: martingales, markov chains, random walks
Overview
The Optional Stopping Theorem (OST), also called Doob's optional sampling theorem, states that under suitable conditions, the expected value of a martingale at a stopping time T equals its initial value: E[M_T] = E[M_0]. This powerful result has applications to gambling (gambler's ruin), random walks (first passage times), and finance (pricing by risk-neutral expectations). The key subtlety is that naive application can fail for unbounded stopping times, so verifying the integrability conditions is essential.
Intuition
In a fair coin-flipping game, no matter how clever your stopping strategy, you cannot expect to come out ahead. If you decide to stop when your wealth first reaches +10 or -5, your expected wealth at stopping still equals your starting wealth (0). The OST formalizes this: for a fair game (martingale), any stopping rule that does not game the future cannot change the expected outcome. The conditions on T prevent pathological strategies like 'stop only when I am ahead' that exploit the infinite horizon.
Formal Definition
Let {M_n, F_n} be a martingale and T be a stopping time. The Optional Stopping Theorem gives conditions under which E[M_T] = E[M_0].
Notation
| Notation | Meaning |
|---|---|
| Stopping time: T is F-measurable and {T <= n} is in F_n | |
| Martingale value at the stopping time T | |
| Minimum of n and T; used for stopped process M_{n wedge T} |
Theorems
Worked Examples
- 1
S_n is a martingale (fair game). The stopping time T = inf{n: S_n = 0 or S_n = 10} is bounded by the first exit from {0,...,10}.
- 2
Let p = P(reach 10). Then E[S_T] = 10p + 0(1-p) = 10p. Set equal to 5.
✓ Answer
P(reach $10 before $0) = 1/2. By symmetry: starting at $5 with barriers at 0 and 10, the probability equals 5/10 = 1/2.
Practice Problems
A fair coin is flipped repeatedly. Let T be the first time the cumulative number of heads exceeds the number of tails by 3. Use OST to find E[T].
Explain why the OST can fail when E[T] = infinity, providing a concrete counterexample using the simple random walk.
Common Mistakes
E[M_T] = M_0 holds for any stopping time
OST requires integrability conditions. For a simple random walk, T = first time hitting 1 has E[T] = infinity and E[M_T] = 1 does not equal M_0 = 0.
Any clever stopping rule can beat a fair game
OST proves that no stopping rule satisfying the integrability conditions can change the expected value of a fair game from its starting value.
Quiz
Historical Background
The optional stopping theorem was formalized by Joseph Leo Doob in his foundational work on martingale theory in the 1940s and 1950s. The result captures the mathematical principle that you cannot beat a fair game by choosing a clever stopping rule. It generalizes earlier results on the gambler's ruin problem and provides a unified framework for first-passage analysis in Markov chains and Brownian motion.
- 1940s
Doob formalizes the optional stopping theorem as part of martingale theory
Joseph Leo Doob
- 1953
Doob's monograph establishes OST as a central tool in probability
Joseph Leo Doob
- 1970s
OST applied to option pricing and mathematical finance
Summary
- The Optional Stopping Theorem states E[M_T] = E[M_0] for a martingale stopped at T, under conditions ensuring T is not exploiting the infinite future.
- Three sufficient conditions: T bounded a.s.; bounded increments with finite mean stopping time; dominated stopped process.
- Gambler's ruin: starting at k with barriers 0 and N, ruin probability = k/N and expected duration = k(N-k), both derived via OST.
- Wald's identity: E[S_T] = mu * E[T] for i.i.d. increments with mean mu and integrable stopping time T.
References
- BookDurrett, R. -- Probability: Theory and Examples, 4th ed., Chapter 4
- BookRoss, S. -- Introduction to Probability Models
Mathematics