foundations of probability
Exchangeability
You should know: random variables, independence of events
Overview
A sequence of random variables X_1, X_2, ... is exchangeable if the joint distribution is invariant under any finite permutation of indices. Exchangeability is strictly weaker than independence (every i.i.d. sequence is exchangeable, but not conversely) and strictly stronger than stationarity. De Finetti's theorem characterizes exchangeable sequences as conditionally i.i.d. given a latent parameter -- a cornerstone of Bayesian statistics justifying the use of prior distributions.
Intuition
Exchangeable variables are 'symmetric': the order does not matter for the joint distribution. Drawing balls without replacement from an urn is exchangeable (but not independent): P(X_1 = red, X_2 = blue) = P(X_1 = blue, X_2 = red). The key insight from de Finetti: if you cannot tell the order, there must be hidden information (a latent theta) conditioning on which the variables ARE independent. Exchangeability is the Bayesian version of 'data are i.i.d. up to unknown parameters.'
Formal Definition
A sequence X_1, X_2, ... of random variables is (infinitely) exchangeable if for every n and every permutation sigma of {1,...,n}, the joint distributions of (X_1,...,X_n) and (X_{sigma(1)},...,X_{sigma(n)}) are equal. A finite sequence is finitely exchangeable if this holds for all permutations.
Notation
| Notation | Meaning |
|---|---|
| Permutation of indices {1,...,n} | |
| De Finetti mixing measure on the space of latent parameters |
Theorems
Worked Examples
- 1
Count equally likely orderings. Total ways to arrange 5 balls: 5! = 120. P(X_1=R, X_2=B): choose 1 of 3 reds first, then 1 of 2 blues: 3*2=6 ways for first two draws, from 5*4=20 possible ordered pairs.
- 2
P(X_1=B, X_2=R): 2/5 * 3/4 = 6/20 = 3/10. Same probability!
- 3
P(X_1=R, X_2=B) = P(X_1=B, X_2=R) = 3/10. The marginal pairs are exchangeable.
✓ Answer
Sampling without replacement is exchangeable: P(X_1=R, X_2=B) = P(X_1=B, X_2=R) = 3/10.
Practice Problems
Are the order statistics X_(1) <= X_(2) <= ... <= X_(n) of i.i.d. random variables exchangeable? Why or why not?
A coin is flipped repeatedly, but the bias theta is drawn once from Uniform[0,1] and fixed for all flips. Are the resulting flips exchangeable? Are they i.i.d.?
Common Mistakes
Thinking exchangeable sequences are always independent
Exchangeable sequences can be highly correlated. The latent variable theta introduces positive correlation: knowing X_1 = 1 raises P(X_2 = 1) because it gives information about theta.
Confusing finite and infinite exchangeability
Finite exchangeability (invariance under permutations of n indices) does NOT imply infinite exchangeability. Only infinite exchangeability gives de Finetti's representation.
Quiz
Summary
- X_1, X_2, ... is exchangeable if the joint distribution is invariant under finite permutations.
- Hierarchy: i.i.d. => exchangeable => stationary. Neither implication reverses.
- Sampling without replacement is finitely but not infinitely exchangeable.
- De Finetti's theorem: infinite exchangeability iff X_i are conditionally i.i.d. given a latent theta.
- Bayesian interpretation: the prior on theta encodes the de Finetti mixing measure.
References
- BookAldous, D. -- Exchangeability and Related Topics (Lecture Notes in Mathematics)
- BookDurrett, R. -- Probability: Theory and Examples, Chapter 6
- WebsiteWikipedia -- Exchangeability
Mathematics