Mathematics.

differential geometry

Integration on Manifolds

Measure Theory120 minDifficulty9 out of 10

You should know: lebesgue integral, de rham cohomology

Overview

Integration on manifolds generalises the Riemann and Lebesgue integrals to smooth manifolds. The correct objects to integrate are not functions but differential forms: an n-form on an oriented n-dimensional manifold can be integrated coordinate-independently. The fundamental theorem of calculus generalises to Stokes' theorem, which unifies the classical theorems of Green, Gauss, and Stokes. For Riemannian manifolds, the metric also gives a canonical volume form enabling integration of functions.

Intuition

On a curved surface in R³ you cannot simply 'lay a coordinate grid' and integrate, because coordinates distort area. A differential n-form carries its own notion of signed volume element that transforms correctly under coordinate changes — it is exactly what you need to integrate intrinsically. The wedge product ∧ encodes orientation: swapping two covectors changes the sign, mirroring the signed-area interpretation of the determinant.

Formal Definition

Definition

Let M be a smooth oriented n-manifold (possibly with boundary ∂M). A differential n-form ω ∈ Ω^n(M) on M is integrated as follows.

Mω=αϕα(Uα)(ϕα1)(ραω)\int_M \omega = \sum_\alpha \int_{\phi_\alpha(U_\alpha)} (\phi_\alpha^{-1})^* (\rho_\alpha \omega)

Integration via partition of unity {ρ_α} subordinate to atlas {(U_α, φ_α)}

INT-FORM
Mdω=Mω\int_M d\omega = \int_{\partial M} \omega

Stokes' theorem (ω ∈ Ω^{n-1}(M), M compact oriented n-manifold with boundary)

STOKES
dvolg=det(gij)dx1dxnd\text{vol}_g = \sqrt{\det(g_{ij})} \, dx^1 \wedge \cdots \wedge dx^n

Riemannian volume form in local coordinates

VOL-FORM

Notation

NotationMeaning
Ωk(M)\Omega^k(M)Space of smooth k-forms on manifold M
d:ΩkΩk+1d : \Omega^k \to \Omega^{k+1}Exterior derivative
Mω\int_M \omegaIntegral of an n-form over an oriented n-manifold M
dvolgd\text{vol}_gRiemannian volume form associated to metric g
φω\varphi^* \omegaPullback of form ω under smooth map φ

Proofs

Well-definedness of ∫_M ω (independent of partition of unity)
  1. Let {ρα},{σβ} be two partitions of unity\text{Let } \{\rho_\alpha\}, \{\sigma_\beta\} \text{ be two partitions of unity}(Both subordinate to respective atlases)
  2. α(ϕα1)(ραω)=α,β(ϕα1)(ρασβω)\sum_\alpha \int (\phi_\alpha^{-1})^*(\rho_\alpha \omega) = \sum_{\alpha,\beta} \int (\phi_\alpha^{-1})^*(\rho_\alpha \sigma_\beta \omega)(Since Σ_β σ_β = 1)
  3. =β,α(ψβ1)(σβραω)= \sum_{\beta,\alpha} \int (\psi_\beta^{-1})^*(\sigma_\beta \rho_\alpha \omega)(By the change-of-variables formula for forms: pulling back by ψ_β⁻¹ introduces the Jacobian, which equals the transformation rule for n-forms, so the sum is symmetric)
  4. =β(ψβ1)(σβω)= \sum_\beta \int (\psi_\beta^{-1})^*(\sigma_\beta \omega)(Using Σ_α ρ_α = 1)

Theorems

Theorem 1: Stokes' Theorem
Let M be a compact oriented n-manifold with boundary and ωΩn1(M). Then: Mdω=Mω\text{Let } M \text{ be a compact oriented } n\text{-manifold with boundary and } \omega \in \Omega^{n-1}(M). \text{ Then: } \int_M d\omega = \int_{\partial M} \omega
Theorem 2: De Rham's Theorem
Integration of forms induces an isomorphism HdRk(M)Hk(M;R) between de Rham and singular cohomology\text{Integration of forms induces an isomorphism } H^k_{\text{dR}}(M) \xrightarrow{\sim} H^k(M; \mathbb{R}) \text{ between de Rham and singular cohomology}
Theorem 3: Change of Variables on Manifolds
If φ:MN is an orientation-preserving diffeomorphism and ωΩn(N), then Mφω=Nω\text{If } \varphi : M \to N \text{ is an orientation-preserving diffeomorphism and } \omega \in \Omega^n(N), \text{ then } \int_M \varphi^* \omega = \int_N \omega
Theorem 4: Divergence Theorem (Gauss)
Mdiv(X)dvolg=MX,νdvolgM\int_M \text{div}(X) \, d\text{vol}_g = \int_{\partial M} \langle X, \nu \rangle \, d\text{vol}_{g|_{\partial M}}

Applications

Maxwell's equations in their covariant form dF = 0 and d*F = J are integrated via Stokes' theorem over 2-manifolds and 3-manifolds in spacetime.

Worked Examples

  1. Write F·dr as a 1-form ω = y dx - x dy.

  2. Compute dω:

    dω=dydxdxdy=dxdydxdy=2dxdyd\omega = dy \wedge dx - dx \wedge dy = -dx\wedge dy - dx\wedge dy = -2\,dx\wedge dy
  3. Apply Stokes' theorem:

    Cω=Ddω=D(2)dxdy=2Area(D)=2π\oint_C \omega = \int_D d\omega = \int_D (-2)\, dx\wedge dy = -2 \cdot \text{Area}(D) = -2\pi

Answer: ∮_C F·dr = -2π.

Practice Problems

Difficulty 8/10

Prove that for a closed form ω (dω = 0), ∫_M dω = 0, and deduce that the integral ∫_C ω over a cycle C depends only on the cohomology class [ω].

Difficulty 9/10

Let M be a compact orientable Riemannian n-manifold without boundary. Show that every harmonic function f (Δf = 0) is constant.

Difficulty 9/10

Prove that every exact form is closed (d² = 0), and give an example showing the converse fails globally but holds locally (Poincaré lemma).

Common Mistakes

Common Mistake

Integration of a function on a manifold is the same as integration of a 0-form

A function f is a 0-form, but to integrate it we need a volume form: ∫_M f = ∫_M f · dvol_g. The volume form provides the 'measure element' and depends on the Riemannian metric or the choice of orientation. Without it, ∫_M f is not defined on a general manifold.

Common Mistake

Stokes' theorem requires the manifold to be embedded in Euclidean space

Stokes' theorem is an intrinsic theorem — it holds for any compact oriented manifold with boundary, with no embedding required. The proof uses only the structure of differential forms and the definition of the integral.

Historical Background

Green (1828) and Gauss (1813) stated special cases of the divergence theorem. Stokes attributed the general theorem to Kelvin (1850); it appeared as an examination question at Cambridge set by Stokes. Cartan (1899–1945) developed the calculus of exterior differential forms that provides the modern framework. De Rham (1931) proved that integration of forms provides the isomorphism between de Rham cohomology and singular cohomology.

  1. 1813

    Gauss states the divergence theorem in special cases

    Carl Gauss

  2. 1828

    Green's theorem in the plane

    George Green

  3. 1850

    Stokes' theorem (attributed to Kelvin) appears in Cambridge exams

    George Stokes, Lord Kelvin

  4. 1899

    Cartan begins developing exterior differential forms

    Élie Cartan

  5. 1931

    De Rham proves his cohomology theorem via integration of forms

    Georges de Rham

Summary

  • Differential n-forms are the correct objects to integrate on oriented n-manifolds, transforming correctly under coordinate changes.
  • The Riemannian volume form dvol_g = √det(g_{ij}) dx¹∧...∧dxⁿ enables integration of functions on a Riemannian manifold.
  • Stokes' theorem ∫_M dω = ∫_{∂M} ω unifies the fundamental theorem of calculus, Green's theorem, and the divergence theorem.
  • De Rham's theorem: integration gives an isomorphism H^k_{dR}(M) ≅ H^k(M; R).
  • Closed forms are locally exact (Poincaré lemma); global obstructions are measured by de Rham cohomology.

References

  1. BookLee, J.M. (2013). Introduction to Smooth Manifolds (2nd ed.). Springer.
  2. BookTu, L.W. (2011). An Introduction to Manifolds (2nd ed.). Springer.