function spaces
Lᵖ Spaces
You should know: lebesgue integral, measurable functions, measure spaces
Overview
The L^p spaces (1 <= p <= ∞) are Banach spaces of measurable functions on a measure space (X, F, mu), equipped with the L^p norm. They provide the natural function spaces for Fourier analysis, PDEs, probability theory, and functional analysis. The cases p = 1 (integrable functions), p = 2 (square-integrable, a Hilbert space), and p = ∞ (essentially bounded) are most frequently encountered.
Intuition
L^p spaces measure 'how large' functions are in an average sense controlled by p. Large p punishes large peaks more severely. L^1 measures total area; L^2 measures total squared amplitude (energy, in physics); L^∞ measures the essential supremum. The triangle inequality (Minkowski's inequality) makes the L^p norm well-behaved, and completeness (every Cauchy sequence converges) makes L^p a Banach space.
Formal Definition
Let (X, F, mu) be a measure space and 1 <= p < ∞.
Notation
| Notation | Meaning |
|---|---|
| L^p norm of f | |
| L^p space with measure mu | |
| L^p space on (a,b) with Lebesgue measure | |
| Essential supremum — supremum ignoring null sets | |
| Dual space of L^p is L^q (1 < p < ∞) |
Properties
L^p is a Banach space
Condition: Completeness proven via Riesz–Fischer theorem
L^2 is a Hilbert space
Containment for finite measure spaces
Dual space
Condition: Requires sigma-finiteness for p = 1
Dense subsets
Worked Examples
Compute the L^1 norm.
Compute the L^2 norm squared.
So f ∈ L^1(0,1) but f ∉ L^2(0,1), showing L^2 ⊄ L^1 in general (though on finite measure spaces L^2 ⊆ L^1).
Answer: f(x) = x^{-1/2} is in L^1(0,1) but not in L^2(0,1).
Practice Problems
For which values of alpha is f(x) = |x|^alpha in L^p(-1,1)?
Prove Holder's inequality for p = 2 (Cauchy–Schwarz inequality): ∫|fg| dmu <= ||f||_2 ||g||_2.
Give an example showing that L^2(R) ⊄ L^1(R).
Common Mistakes
L^p ⊆ L^q whenever p < q, on any measure space
On finite measure spaces L^q ⊆ L^p for p <= q. On infinite measure spaces (like R with Lebesgue measure), neither L^p nor L^q contains the other in general.
The L^p norm is defined on individual functions
Strictly, L^p consists of equivalence classes of functions where f ~ g if f = g a.e. The 'norm' ||f||_p is zero for all a.e.-zero functions, so we must identify them to get a genuine norm.
Pointwise convergence implies L^p convergence
Pointwise (or a.e.) convergence does not imply L^p convergence. DCT gives L^p convergence under additional domination. The example f_n = n · 1_{(0,1/n)} converges a.e. to 0 but ||f_n||_1 = 1.
Quiz
Historical Background
The L^p spaces emerged naturally from Lebesgue's integration theory in the early 20th century. Frigyes Riesz systematically studied L^p in 1910, proving what is now called the Riesz–Fischer theorem (L^2 is complete). The H"older and Minkowski inequalities, essential to establishing the norm structure, were classical results adapted to the Lebesgue setting.
- 1910
Riesz proves completeness of L^2 (Riesz-Fischer theorem)
Frigyes Riesz, Ernst Fischer
- 1913
Riesz extends to general L^p spaces
Frigyes Riesz
- 1927
Riesz representation for L^p dualities clarified
Frigyes Riesz
Summary
- L^p(mu) is the Banach space of (equivalence classes of) measurable functions with finite L^p norm ||f||_p = (∫|f|^p dmu)^{1/p}.
- L^2 is the only L^p space that is a Hilbert space, with inner product ⟨f,g⟩ = ∫fg dmu.
- Holder's inequality: ∫|fg| dmu <= ||f||_p ||g||_q where 1/p + 1/q = 1.
- Minkowski's inequality: ||f+g||_p <= ||f||_p + ||g||_p (triangle inequality for L^p).
- On finite measure spaces L^q ⊆ L^p for p <= q; this fails on infinite measure spaces.
References
- BookFolland — Real Analysis, 2nd ed. (1999), §6.1–§6.2
- BookRudin — Real and Complex Analysis, 3rd ed. (1987), Chapter 3
- WebsiteWikipedia — Lp space
Mathematics