foundations of measure theory
Measure Spaces
You should know: sigma algebras
Overview
A measure space is the fundamental structure of measure theory: a set X equipped with a σ-algebra ℱ and a function μ : ℱ → [0, ∞] that assigns a 'size' to every measurable set in a consistent way. This framework generalises length on ℝ, area in ℝ², counting on discrete sets, and probability on sample spaces, all within a single axiomatic system.
Intuition
Imagine a weighing scale for subsets of X. The σ-algebra tells you which subsets you are 'allowed' to weigh, and the measure μ gives each allowed subset a non-negative weight. Countable additivity — the key axiom — says the total weight of disjoint pieces equals the sum of the individual weights, just as physical mass behaves when you cut an object into separate pieces.
Formal Definition
A measure space is a triple (X, ℱ, μ) where X is a set, ℱ is a σ-algebra on X, and μ is a measure: a function satisfying the following axioms.
Notation
| Notation | Meaning |
|---|---|
| Measure space | |
| Measure of a set A ∈ ℱ | |
| Almost everywhere — a property holding except on a set of measure zero | |
| μ is absolutely continuous with respect to ν |
Properties
Monotonicity
Condition: A, B ∈ ℱ
Countable subadditivity
Condition: A₁, A₂, … ∈ ℱ (not necessarily disjoint)
Continuity from below
Condition: Increasing sequence Aₙ ↗ A in ℱ
Continuity from above
Condition: Decreasing sequence Aₙ ↘ A in ℱ with μ(A₁) < ∞
Worked Examples
Define μ(A) = |A| (cardinality of A) for A ⊆ ℕ, with μ(A) = ∞ for infinite A.
μ(∅) = 0 since ∅ has no elements.
For pairwise disjoint A₁, A₂, … ⊆ ℕ, the elements of their union are exactly the elements of each Aₙ, with no repetition, so total count is the sum of individual counts.
Answer: (ℕ, 2^ℕ, μ_#) is a valid measure space.
Practice Problems
Prove the inclusion–exclusion formula: for A, B ∈ ℱ with μ(A), μ(B) < ∞, μ(A ∪ B) = μ(A) + μ(B) − μ(A ∩ B).
Show that if μ(Aₙ) = 0 for all n ∈ ℕ, then μ(∪ₙ Aₙ) = 0.
Give an example showing that continuity from above fails without the assumption μ(A₁) < ∞.
Common Mistakes
Confusing σ-additivity with finite additivity
σ-additivity requires the property to hold for countably infinite disjoint collections. Finite additivity alone does not imply σ-additivity, and many pathological set functions satisfy the latter but not the former.
Assuming continuity from above always holds
Continuity from above requires μ(A₁) < ∞. Without this, the property can fail spectacularly (e.g., counting measure on tail sets of ℕ).
Treating null sets as 'nonexistent'
A null set has measure zero but may be non-empty (e.g., the Cantor set has Lebesgue measure zero but is uncountable). Properties holding 'almost everywhere' still allow failure on null sets.
Quiz
Historical Background
Henri Lebesgue's 1902 thesis introduced the measure-space framework to solve the deficiencies of the Riemann integral — in particular, the inability to integrate many pointwise limits of functions. His key insight was to measure the pre-image of intervals rather than partition the domain, yielding a far more powerful integration theory.
- 1902
Lebesgue introduces his measure and integral
Henri Lebesgue
- 1910s
Carathéodory develops outer measure and the extension theorem
Constantin Carathéodory
- 1933
Kolmogorov axiomatises probability theory using measure spaces
Andrei Kolmogorov
Summary
- A measure space (X, ℱ, μ) consists of a set, a σ-algebra, and a countably additive non-negative function μ on ℱ.
- Key derived properties include monotonicity, countable subadditivity, and continuity from below/above.
- Continuity from above requires μ(A₁) < ∞; this hypothesis cannot be dropped.
- A measure space is finite if μ(X) < ∞ and σ-finite if X is a countable union of finite-measure sets.
- Null sets (sets of measure zero) play a central role — properties holding off null sets hold 'almost everywhere'.
References
- BookFolland, G.B. — Real Analysis, 2nd ed. (1999), §1.1–§1.2
- BookRoyden, H.L. & Fitzpatrick, P.M. — Real Analysis, 4th ed. (2010), Chapter 17
Mathematics