linear representations
Schur's Lemma
You should know: irreducible representations
Overview
Schur's lemma is a foundational result in representation theory stating that a G-equivariant map between irreducible representations is either zero or an isomorphism, and over an algebraically closed field every G-equivariant endomorphism of an irreducible representation is a scalar multiple of the identity. This deceptively simple statement has far-reaching consequences: it underpins the orthogonality of irreducible characters, the block-diagonal structure of the group algebra, and the representation theory of algebras.
Intuition
A G-equivariant map φ: V → W must send G-invariant subspaces of V to G-invariant subspaces of W. If V is irreducible, ker(φ) is either 0 or V; if W is irreducible, Im(φ) is either 0 or W. So either φ = 0 or φ is an isomorphism. Over ℂ, a G-equivariant endomorphism must have an eigenvalue (since ℂ is algebraically closed), and the eigenspace is G-stable — irreducibility then forces it to be all of V.
Formal Definition
Let G be a group and V, W irreducible representations over a field k.
Notation
| Notation | Meaning |
|---|---|
| Space of G-equivariant (intertwining) maps from V to W | |
| G-equivariant endomorphisms of V |
Properties
Schur's lemma for algebras
Division ring structure
Theorems
Worked Examples
- 1
Let φ: V → W be a non-zero G-equivariant map. ker(φ) is a G-invariant subspace of V.
- 2
Since V is irreducible, ker(φ) = 0 (as φ ≠ 0) or ker(φ) = V. Since φ ≠ 0, ker(φ) = 0, so φ is injective.
- 3
Im(φ) is a non-zero G-invariant subspace of W. Since W is irreducible, Im(φ) = W, so φ is surjective.
✓ Answer
φ is both injective and surjective, hence an isomorphism.
Practice Problems
Show that every irreducible representation of an abelian group over ℂ is 1-dimensional using Schur's lemma.
Explain why Schur's lemma fails to give End_G(V) = k over ℝ, and give an example.
Common Mistakes
Assuming Schur's lemma forces End_G(V) = k over any field
Part 2 requires k to be algebraically closed. Over ℝ, for example, End_G(V) can be ℂ or ℍ (quaternions), since these are the only finite-dimensional division algebras over ℝ.
Thinking Schur's lemma applies only to finite groups
Schur's lemma holds for any group, algebra, or ring: it is a statement about simple modules. It applies equally to Lie algebra representations, module categories, and abstract algebra.
Quiz
Historical Background
Issai Schur proved this lemma in his 1905 dissertation 'Über eine Klasse von Matrizen'. The result provided the key to unlocking character orthogonality and the structure of the group algebra as a product of matrix algebras (Wedderburn's theorem). The lemma's simplicity belies its power: in the hands of subsequent mathematicians it became one of the most-used tools in algebra, from finite group theory to infinite-dimensional representation theory.
- 1905
Schur proves the lemma in his dissertation on matrix classes
Issai Schur
- 1907
Wedderburn structure theorem (related via Schur's lemma)
Joseph Wedderburn
- 1920s
Weyl applies Schur's lemma to classify irreps of compact Lie groups
Hermann Weyl
Summary
- Schur's Lemma Part 1: a non-zero G-equivariant map between irreducible representations is an isomorphism.
- Schur's Lemma Part 2: over an algebraically closed field, End_G(V) = k·id for irreducible V.
- Consequence: Hom_G(V, W) = k if V ≅ W, and 0 otherwise (over algebraically closed k).
- Schur's lemma implies the orthogonality of characters and the Wedderburn decomposition of the group algebra.
- The lemma generalises to simple modules over any ring.
References
- BookSerre, J.-P. — Linear Representations of Finite Groups (1977), §1.4
- BookLang, S. — Algebra, 3rd ed. (2002), Chapter XVIII §1
- WebsiteWikipedia — Schur's lemma
- WebsiteMathWorld — Schur's Lemma
Mathematics