functional analysis
Spectral Theory of Operators
You should know: hilbert spaces, eigenvalues and eigenvectors
Overview
Spectral theory extends the notion of eigenvalues and eigenvectors from finite-dimensional linear algebra to operators on infinite-dimensional Banach and Hilbert spaces. The spectrum of an operator \(T\) replaces the finite set of eigenvalues and decomposes into the point spectrum (eigenvalues), continuous spectrum, and residual spectrum. For bounded self-adjoint operators on Hilbert spaces, the spectral theorem provides a complete decomposition analogous to diagonalisation: every such operator can be realised as a multiplication operator on an \(L^2\) space, encoded by a projection-valued measure.
Intuition
In finite dimensions, every symmetric matrix can be diagonalised. Spectral theory asks: can we diagonalise an infinite-dimensional operator? For compact self-adjoint operators the answer is an exact analogue of the finite case—eigenvalues accumulate only at 0, and eigenvectors form a complete orthonormal basis. For general bounded self-adjoint operators, diagonalisation requires a continuum of generalised eigenvectors encoded by a spectral measure. The spectrum is the set of values at which the operator almost fails to be invertible.
Formal Definition
Let \(T \in \mathcal{B}(X)\) be a bounded linear operator on a complex Banach space \(X\). The resolvent set is \(\rho(T) = \{\lambda \in \mathbb{C} : (T - \lambda I)^{-1} \in \mathcal{B}(X)\}\). The spectrum is \(\sigma(T) = \mathbb{C} \setminus \rho(T)\). The spectrum decomposes as: point spectrum \(\sigma_p(T)\) where \(T - \lambda I\) is not injective; continuous spectrum \(\sigma_c(T)\) where \(T - \lambda I\) is injective with dense but not closed range; residual spectrum \(\sigma_r(T)\) where \(T - \lambda I\) is injective but the range is not dense.
Properties
Spectrum of self-adjoint operator is real
Spectrum of unitary operator lies on unit circle
Eigenvectors for distinct eigenvalues of self-adjoint operators are orthogonal
Theorems
Worked Examples
Point spectrum: \(\lambda \in \sigma_p(M_\phi)\) iff \(\phi(x) = \lambda\) on a set of positive measure. Since \(\{x = \lambda\}\) has measure zero for every \(\lambda\), \(\sigma_p(M_\phi) = \emptyset\).
Resolvent: \((M_\phi - \lambda I)^{-1}\) acts by multiplication by \(1/(x-\lambda)\). This is bounded iff \(1/(x-\lambda) \in L^\infty([0,1])\), which fails when \(\lambda \in [0,1]\).
For \(\lambda \notin [0,1]\), \(1/(x-\lambda)\) is bounded on \([0,1]\), so \(\lambda \in \rho(M_\phi)\). Hence \(\sigma(M_\phi) = [0,1]\).
Since \(M_\phi - \lambda I\) is injective for all \(\lambda \in [0,1]\) (multiplication by \(x-\lambda\) is injective on \(L^2\)) but not boundedly invertible, the entire interval \([0,1]\) is in \(\sigma_c(M_\phi)\).
Answer: \(\sigma(M_x) = [0,1]\) with purely continuous spectrum; no eigenvalues.
Practice Problems
Prove that the spectrum of a bounded operator on a complex Banach space is nonempty.
Compute \(\sigma(S)\) and \(\sigma(S^*)\) where \(S\) is the unilateral right shift on \(\ell^2\): \(S(x_1, x_2, \ldots) = (0, x_1, x_2, \ldots)\).
Prove that eigenvectors of a self-adjoint operator corresponding to distinct eigenvalues are orthogonal.
Common Mistakes
The spectrum consists only of eigenvalues
In infinite dimensions the spectrum has three disjoint parts: point spectrum (eigenvalues), continuous spectrum, and residual spectrum. The multiplication operator \(M_x\) on \(L^2([0,1])\) has spectrum \([0,1]\) but no eigenvalues.
Spectral radius always equals the operator norm
The spectral radius \(r(T) = \lim \|T^n\|^{1/n} \le \|T\|\); equality holds for normal operators (\(T^*T = TT^*\)) but fails for non-normal ones. The nilpotent matrix \(\begin{pmatrix}0&1\\0&0\end{pmatrix}\) has norm 1 but spectral radius 0.
Quiz
Summary
- The spectrum \(\sigma(T)\) is the set of \(\lambda\) for which \(T - \lambda I\) fails to be boundedly invertible; it is always compact and nonempty for bounded operators on complex Banach spaces.
- The spectrum decomposes into point spectrum (eigenvalues), continuous spectrum, and residual spectrum.
- Spectral radius formula: \(r(T) = \lim_n \|T^n\|^{1/n}\); for self-adjoint operators \(r(T) = \|T\|\).
- Self-adjoint operators on Hilbert spaces have real spectrum and admit the spectral theorem: \(T = \int \lambda\,dE(\lambda)\).
- Compact self-adjoint operators have a countable spectrum accumulating only at 0, with eigenvectors forming a complete orthonormal basis.
References
- BookRudin, W. Functional Analysis. 2nd ed., McGraw-Hill, 1991. Chapters 10–12.
- BookReed, M. and Simon, B. Methods of Modern Mathematical Physics, Vol. 1. Academic Press, 1980.
- WebsiteWikipedia — Spectral theory
Mathematics