differential calculus
Extreme Value Theorem
You should know: continuity
Overview
The Extreme Value Theorem (EVT) guarantees that a continuous function on a closed, bounded interval [a,b] attains both a maximum and a minimum value somewhere on that interval. It's an existence theorem: it doesn't say how to find the extrema, only that they're guaranteed to exist, which is what makes optimization on closed intervals well-posed.
Interactive Graph
Formal Definition
If f is continuous on the closed interval [a,b], then there exist points c, d in [a,b] such that:
f(c) is the absolute minimum and f(d) is the absolute maximum of f on [a,b]
Worked Examples
f is a polynomial, hence continuous everywhere, so it's continuous on the closed interval [0,5] — EVT applies.
Find critical points: f'(x) = 2x - 4 = 0 ⟹ x = 2 (in [0,5]).
Evaluate f at the critical point and both endpoints: f(0)=3, f(2)=-1, f(5)=8.
Answer: Absolute minimum is -1 at x=2; absolute maximum is 8 at x=5.
Practice Problems
Find the absolute maximum and minimum of f(x) = x³ - 3x on [-2, 2].
A simply-supported beam's bending moment is M(x) = 400x − 50x² (N·m) for 0 ≤ x ≤ 8 m. Find the location and value of the maximum bending moment.
Quiz
Summary
- The Extreme Value Theorem states a function continuous on a closed interval [a,b] must attain an absolute max and absolute min on that interval.
- It is an existence theorem — it guarantees extrema exist without telling you where they are.
- Both hypotheses matter: continuity and closedness of the interval. Drop either and the guarantee fails.
- In practice, find extrema by checking f at critical points (where f'=0 or f' doesn't exist) and at the endpoints.
Mathematics