submanifold geometry
Calibrated Geometry
You should know: differential forms, riemannian metric
Overview
Calibrated geometry, introduced by Harvey and Lawson in 1982, provides a powerful method for identifying volume-minimizing submanifolds. A calibration is a closed differential p-form φ on a Riemannian manifold M such that φ restricts to ≤ vol on every tangent p-plane. A submanifold N is calibrated by φ if φ restricts to exactly the volume form of N; such submanifolds are automatically volume-minimizing in their homology class. Key examples include holomorphic submanifolds (calibrated by powers of the Kähler form) and special Lagrangian submanifolds in Calabi-Yau manifolds.
Intuition
Think of a calibration as a 'certificate of minimality.' If you can show that a submanifold N achieves the maximum value of the calibration form in every tangent direction, then N cannot be shrunk: any competitor with the same boundary has at least as large a volume. It is like a soap film — nature minimizes area, and soap films are (locally) area-minimizing. Calibrated submanifolds are the algebraic-geometry analog of soap films, arising naturally in spaces with special holonomy.
Formal Definition
Let (M, g) be a Riemannian manifold. A calibration of degree p is a closed p-form φ ∈ Ω^p(M) (dφ = 0) such that for every point x ∈ M and every oriented p-dimensional subspace ξ ⊆ T_xM:
Equivalently, φ(e₁,...,eₚ) ≤ 1 for every orthonormal frame e₁,...,eₚ
Theorems
Worked Examples
- 1
On ℂⁿ with coordinates (z₁,...,zₙ), the Kähler form is ω = i/2 Σⱼ dzⱼ ∧ dz̄ⱼ = Σⱼ dxⱼ ∧ dyⱼ (where zⱼ = xⱼ + iyⱼ). This is closed: dω = 0.
- 2
Check the calibration condition: for an oriented 2-plane ξ with orthonormal basis {u, v}: ω(u,v) = Σⱼ (dxⱼ∧dyⱼ)(u,v). By the Cauchy-Schwarz inequality for the 2-form ω and the standard inner product, |ω(u,v)| ≤ |u||v| = 1 with equality iff ξ is a complex line (v = Ju for the standard complex structure J).
- 3
For a complex curve Σ ⊂ ℂⁿ (complex dimension 1, real dimension 2), at each point T_pΣ is a complex line, so the complex structure J maps T_pΣ to itself. An orthonormal basis {u, Ju} gives ω(u,Ju) = g(u,u) = 1 = vol(u,Ju).
- 4
So holomorphic curves are calibrated by ω, hence volume-minimizing. This is the algebro-geometric fact that holomorphic curves minimize area.
✓ Answer
The Kähler form ω is a calibration: ω(u,v) ≤ 1 for any orthonormal 2-frame, with equality iff the plane is a complex line. Complex curves (Jξ = ξ) achieve equality, so they are calibrated and volume-minimizing.
Practice Problems
State the definition of a calibration and explain why a calibrated submanifold is volume-minimizing. What role does the closedness dφ = 0 play?
List the main calibrations associated to manifolds with special holonomy (from Berger's list) and the corresponding calibrated submanifolds.
Quiz
Summary
- A calibration φ is a closed p-form with φ|_ξ ≤ vol_ξ for all oriented p-planes; calibrated submanifolds achieve equality and minimize volume in their homology class.
- Harvey-Lawson theorem: dφ=0 and calibrated condition ⟹ N minimizes volume (uses Stokes' theorem for homologous cycles).
- Kähler manifolds: ωᵏ/k! calibrates complex k-dimensional submanifolds (holomorphic = minimal).
- Calabi-Yau manifolds: Re(Ω) calibrates special Lagrangians; these are Lagrangian with Im(Ω)|_N = 0.
- Special holonomy manifolds (G₂, Spin(7)) have exceptional calibrations: associative 3-folds, coassociative 4-folds, Cayley 4-folds.
Mathematics