Mathematics.

triangles

Angle Bisectors and Medians

Geometry30 minDifficulty4 out of 10

You should know: triangles

Overview

A median of a triangle is a segment from a vertex to the midpoint of the opposite side; an angle bisector is a segment from a vertex that splits that vertex's angle into two equal halves. Every triangle has three medians and three angle bisectors, and each set meets at a single special point: the three medians meet at the centroid (the triangle's balance point), and the three angle bisectors meet at the incenter (the center of the inscribed circle). These are two of the four classical 'triangle centers' — points defined purely by a triangle's shape, independent of any coordinate system.

Intuition

The centroid is literally the triangle's center of mass: if you cut a triangle out of uniform cardboard, it balances perfectly on a pin placed at the centroid. Each median cuts the triangle into two smaller triangles of equal area (since they share a base half as long, and the same height), which is why three medians concurring at one point balances the whole shape. The incenter, meanwhile, is equidistant from all three sides — it's the one point inside the triangle where you could inscribe the largest possible circle tangent to all three sides, because every point on an angle bisector is equidistant from the two sides forming that angle.

Interactive Graph

Drag a triangle's vertices and watch the centroid and incenter move, with the 2:1 median split highlighted

Loading visualization…

Formal Definition

Definition

For a triangle with vertices A, B, C, sides a, b, c (opposite the correspondingly-named vertex), the median from A to the midpoint of BC has length m_a, and the angle bisector from A meets BC at a point dividing it in ratio AB:AC:

ma2=2b2+2c2a24m_a^2 = \frac{2b^2 + 2c^2 - a^2}{4}
Median length formula (Apollonius's theorem)
BDDC=ABAC=cb\frac{BD}{DC} = \frac{AB}{AC} = \frac{c}{b}
Angle bisector theorem: D is where the bisector from A meets BC
G divides each median 2:1 from vertex to midpointG \text{ divides each median } 2:1 \text{ from vertex to midpoint}
Centroid ratio along each median

Notation

NotationMeaning
GGCentroid — the point where all three medians meet
IIIncenter — the point where all three angle bisectors meet, and the center of the inscribed circle
mam_aLength of the median from vertex A to the midpoint of the opposite side a

Properties

Centroid concurrency and ratio

The three medians of any triangle meet at a single point G, which divides each median 2:1 (vertex-to-G is twice G-to-midpoint).\text{The three medians of any triangle meet at a single point } G \text{, which divides each median } 2:1 \text{ (vertex-to-} G \text{ is twice } G \text{-to-midpoint).}

Median bisects area

Each median splits the triangle into two smaller triangles of equal area.\text{Each median splits the triangle into two smaller triangles of equal area.}

Condition: Follows because the two sub-triangles share the same height from the opposite vertex and have equal-length bases (the two halves of the bisected side).

Incenter concurrency

The three angle bisectors of any triangle meet at a single point I, equidistant from all three sides.\text{The three angle bisectors of any triangle meet at a single point } I \text{, equidistant from all three sides.}

Condition: That common distance is the inradius r, the radius of the triangle's inscribed circle.

Angle bisector theorem

BDDC=ABAC\frac{BD}{DC} = \frac{AB}{AC}

Condition: The bisector of the angle at A divides the opposite side BC in the same ratio as the two adjacent sides.

Applications

The centroid is used to locate the center of mass of triangular structural elements and cross-sections, essential for stability and load calculations.

Worked Examples

  1. Apply Apollonius's theorem with a = 10 (the hypotenuse) and b = 6, c = 8 as the legs.

    ma2=2(6)2+2(8)21024=72+1281004=1004=25m_a^2 = \frac{2(6)^2 + 2(8)^2 - 10^2}{4} = \frac{72+128-100}{4} = \frac{100}{4} = 25
  2. Take the square root.

    ma=25=5m_a = \sqrt{25} = 5

Answer: 5 — exactly half the hypotenuse, a general fact for right triangles (the median to the hypotenuse always equals half the hypotenuse).

Practice Problems

Difficulty 3/10

A median of a triangle has total length 18 from vertex to midpoint. If G is the centroid, how far is G from the vertex?

Difficulty 4/10

Triangle ABC has AB = 10, AC = 15, BC = 20. The bisector from A meets BC at D. Find BD.

Difficulty 5/10

A triangular metal plate has legs 9 and 12 meeting at a right angle, with hypotenuse 15. An engineer needs the distance from the right-angle vertex to the centroid, given that the median from the right-angle vertex to the hypotenuse's midpoint has length 7.5. Find the vertex-to-centroid distance.

Common Mistakes

Common Mistake

Confusing the centroid (medians) with the incenter (angle bisectors) as the same point.

The centroid and incenter coincide only for equilateral triangles; in general, medians and angle bisectors are different segments meeting at different triangle centers.

Common Mistake

Assuming the centroid splits each median into two equal halves (1:1).

The centroid divides each median in a 2:1 ratio — the piece from the vertex to the centroid is twice as long as the piece from the centroid to the midpoint.

Quiz

The point where a triangle's three medians meet is called the:
The centroid divides each median, from vertex to midpoint, in what ratio?
The angle bisector theorem states that a vertex's angle bisector divides the opposite side in the ratio of:

Summary

  • A median joins a vertex to the midpoint of the opposite side; the three medians meet at the centroid, dividing each median 2:1.
  • An angle bisector splits a vertex angle in half; the three angle bisectors meet at the incenter, the center of the inscribed circle.
  • Apollonius's theorem gives median length: m_a² = (2b² + 2c² − a²)/4.
  • The angle bisector theorem: a bisector from A divides the opposite side in the ratio of the two adjacent sides, BD:DC = AB:AC.
  • In a right triangle, the median to the hypotenuse always equals exactly half the hypotenuse.

References