Mathematics.

algebraic structures

Algebraic Number Theory

Number Theory120 minDifficulty9 out of 10

You should know: galois theory, rings

Overview

Algebraic number theory studies the arithmetic of algebraic number fields — finite extensions of the rational numbers. It generalises classical integer arithmetic by replacing \(\mathbb{Z}\) with rings of algebraic integers, revealing deep structure through ideals, class groups, and unit groups.

Intuition

In \(\mathbb{Z}[\sqrt{-5}]\) the number 6 factors as both \(2 \cdot 3\) and \((1+\sqrt{-5})(1-\sqrt{-5})\), breaking unique factorisation. Passing from elements to ideals restores it: the ideal \((6)\) factors uniquely as \(\mathfrak{p}_2 \mathfrak{p}_3 \overline{\mathfrak{p}_3}\). The class group measures how far the ring is from having unique factorisation.

Formal Definition

Definition

Let \(K\) be a number field of degree \(n\) over \(\mathbb{Q}\). The ring of integers \(\mathcal{O}_K\) is the integral closure of \(\mathbb{Z}\) in \(K\).

OK={αK:f(α)=0 for some monic fZ[x]}\mathcal{O}_K = \{ \alpha \in K : f(\alpha) = 0 \text{ for some monic } f \in \mathbb{Z}[x] \}

Ring of integers of a number field

ring-of-integers
Cl(K)=IK/PK\text{Cl}(K) = \mathcal{I}_K / \mathcal{P}_K

Ideal class group: fractional ideals modulo principal ideals

class-group
hK=Cl(K)h_K = |\text{Cl}(K)|

Class number; h_K = 1 iff unique factorisation holds in O_K

class-number

Notation

NotationMeaning
OK\mathcal{O}_KRing of integers of the number field K
Cl(K)\text{Cl}(K)Ideal class group of K
hKh_KClass number of K
N(a)N(\mathfrak{a})Norm of ideal a, equal to |O_K/a|
disc(K)\text{disc}(K)Discriminant of the number field

Theorems

Theorem 1: Dedekind's Theorem (unique factorisation of ideals)
EverynonzeroidealofOKfactorsuniquelyasaproductofprimeideals.Every non-zero ideal of \mathcal{O}_K factors uniquely as a product of prime ideals.
Theorem 2: Minkowski's Bound
EveryidealclasscontainsanintegralidealofnormatmostMK=n!nn(4π)r2disc(K).Every ideal class contains an integral ideal of norm at most M_K = \frac{n!}{n^n}\left(\frac{4}{\pi}\right)^{r_2}\sqrt{|\text{disc}(K)|}.
Theorem 3: Dirichlet's Unit Theorem
OK×μK×Zr1+r21,wherer1isthenumberofrealembeddings,r2thenumberofcomplexconjugatepairs,andμKthegroupofrootsofunityinK.\mathcal{O}_K^\times \cong \mu_K \times \mathbb{Z}^{r_1 + r_2 - 1}, where r_1 is the number of real embeddings, r_2 the number of complex conjugate pairs, and \mu_K the group of roots of unity in K.

Worked Examples

  1. Since \(-5 \equiv 3 \pmod{4}\), the ring of integers is \(\mathbb{Z}[\sqrt{-5}]\) (not the larger \(\mathbb{Z}[(1+\sqrt{-5})/2]\) which applies only when \(d \equiv 1 \pmod{4}\)).

    OK=Z[5]\mathcal{O}_K = \mathbb{Z}[\sqrt{-5}]
  2. Minkowski's bound: \(M_K = \frac{2}{\pi}\sqrt{20} \approx 2.85\), so we need only check primes 2.

    MK=2π202.85M_K = \frac{2}{\pi}\sqrt{|{-20}|} \approx 2.85
  3. The ideal \((2)\) splits: \((2) = (2, 1+\sqrt{-5})^2\). The prime ideal \(\mathfrak{p} = (2, 1+\sqrt{-5})\) satisfies \(\mathfrak{p}^2 = (2)\) but \(\mathfrak{p}\) is not principal (there is no element of norm 2 in \(\mathcal{O}_K\)). Thus \(h_K = 2\).

Answer: \(\mathcal{O}_K = \mathbb{Z}[\sqrt{-5}]\) and \(h_K = 2\).

Practice Problems

Difficulty 7/10

Find the ring of integers of \(\mathbb{Q}(\sqrt{3})\) and determine whether it has unique factorisation (i.e., compute \(h_K\)).

Difficulty 9/10

Prove that every non-zero prime ideal \(\mathfrak{p}\) of \(\mathcal{O}_K\) lies over a unique rational prime \(p\), i.e., \(\mathfrak{p} \cap \mathbb{Z} = (p)\).

Difficulty 8/10

Use Dirichlet's Unit Theorem to determine the structure of \(\mathcal{O}_K^\times\) for \(K = \mathbb{Q}(\sqrt{2})\).

Common Mistakes

Common Mistake

Assuming unique factorisation of elements holds in all rings of integers

Unique factorisation of elements fails whenever \(h_K > 1\); it is ideals that factor uniquely.

Common Mistake

Confusing the ring of integers \(\mathcal{O}_K\) with \(\mathbb{Z}[\alpha]\) for a chosen generator \(\alpha\)

\(\mathbb{Z}[\alpha] \subseteq \mathcal{O}_K\) but equality holds only when \(\{1, \alpha, \ldots, \alpha^{n-1}\}\) is an integral basis.

Historical Background

Kummer introduced ideal numbers in the 1840s to repair a flawed proof of Fermat's Last Theorem, observing that unique factorisation fails in cyclotomic rings. Dedekind recast Kummer's ideas into the language of ideals in 1871, and Hilbert systematised the theory in his Zahlbericht of 1897. The 20th century brought class field theory (Takagi, Artin) and ultimately the Langlands programme.

  1. 1847

    Kummer introduces ideal numbers for cyclotomic fields

    Ernst Kummer

  2. 1871

    Dedekind defines ideals and proves unique factorisation of ideals

    Richard Dedekind

  3. 1897

    Hilbert publishes the Zahlbericht

    David Hilbert

  4. 1920s

    Takagi and Artin develop class field theory

    Teiji Takagi, Emil Artin

Summary

  • Algebraic number theory studies arithmetic in rings of integers \(\mathcal{O}_K\) of number fields \(K/\mathbb{Q}\).
  • Unique factorisation of elements may fail, but Dedekind proved every non-zero ideal factors uniquely into prime ideals.
  • The class group \(\text{Cl}(K)\) is finite; its order \(h_K\) measures failure of unique factorisation.
  • Minkowski's bound makes the class number effectively computable.
  • Dirichlet's Unit Theorem describes the group of units: rank \(r_1 + r_2 - 1\) free part plus roots of unity.

References

  1. BookNeukirch, J. Algebraic Number Theory. Springer, 1999.
  2. BookMarcus, D. Number Fields. Springer, 1977.