vector calculus
Conservative Vector Fields and Potential Functions
You should know: vector fields, line integrals, gradient, divergence and curl
Overview
A vector field F is conservative if it is the gradient of some scalar function f (the potential): F = gradient(f). For conservative fields, line integrals are path-independent: integral_C F dot dr depends only on endpoints. A field is conservative iff its curl is zero (in simply-connected regions). The fundamental theorem for line integrals: integral_C F dot dr = f(B) - f(A).
Intuition
If you push a box on a flat floor, the work done depends on the path (friction). If you lift a box in a gravitational field, the work done depends only on how high you lift it (endpoints), not the path -- gravity is conservative. A conservative field has a 'height function' (potential f) such that F = gradient(f). Going around a closed loop does zero work: all 'uphill' work is returned 'downhill.'
Formal Definition
F: D -> R^n is conservative if F = gradient(f) for some C^1 scalar f (the potential or potential energy function). Equivalent conditions (on a simply connected domain): (1) curl(F) = 0 for F: R^3 -> R^3, or dF_1/dy = dF_2/dx for F: R^2 -> R^2. (2) Line integral is path-independent. (3) Closed-path integrals vanish: contour integral F dot dr = 0. Fundamental theorem: integral_C F dot dr = f(B) - f(A).
Notation
| Notation | Meaning |
|---|---|
| Potential function: F = gradient(f) | |
| Curl of F; zero iff F conservative (simply connected domain) |
Theorems
Worked Examples
- 1
Check: dF_1/dy = 2x + 2y, dF_2/dx = 2x + 2y. Equal, so F is conservative.
- 2
Find f: f_x = 2xy + y^2, so f = x^2y + xy^2 + g(y).
- 3
f_y = x^2 + 2xy + g'(y) = x^2 + 2xy, so g'(y)=0, g = const.
✓ Answer
f(x,y) = x^2*y + xy^2 (+ constant).
Practice Problems
Use the potential to evaluate integral_C (2xy)dx + x^2 dy from (0,0) to (1,2).
Common Mistakes
Concluding a field is conservative from curl F = 0 on a non-simply-connected domain.
curl F = 0 implies conservative only on simply connected domains (no holes). The field F = (-y,x)/(x^2+y^2) has zero curl except at the origin but is not conservative on R^2 minus the origin.
Quiz
Historical Background
Conservative forces appear in classical mechanics -- gravity and electrostatics are conservative. The connection between conservative vector fields, path independence, and potential functions was developed by Gauss, Green, and Stokes in the 19th century. The fundamental theorem for line integrals is the direct multivariable analogue of the single-variable fundamental theorem of calculus.
- 1800s
Gauss and Green develop potential theory for conservative fields
Carl Friedrich Gauss, George Green
Summary
- F conservative iff F = gradient(f) for some potential f.
- On simply connected domains: F conservative iff curl(F) = 0.
- Fundamental theorem: integral_C F dot dr = f(B) - f(A) (path independent).
- Closed loops give zero work for conservative fields.
References
- BookStewart, J. Multivariable Calculus. 8th ed. Brooks/Cole, 2015.
Mathematics